CylindricalDetector.surface¶
- CylindricalDetector.surface(param)[source]¶
Return the detector surface point corresponding to
param
.For parameters
phi
andh
, the returned point is given bysurf = R * (radius * cos(phi), -radius * sin(phi), h) + t
where
R
is a rotation matrix andt
is a translation vector. Note that increase ofphi
corresponds to rotation in the clockwise direction, by analogy to flat detectors.- Parameters:
- param
array-like
or sequence Parameter value(s) at which to evaluate. A sequence of parameters must have length 2.
- param
- Returns:
- point
numpy.ndarray
Vector(s) pointing from the origin to the detector surface point at
param
. Ifparam
is a single parameter, the returned array has shape(3,)
, otherwisebroadcast(*param).shape + (3,)
.
- point
Examples
The method works with a single parameter, resulting in a single vector:
>>> part = odl.uniform_partition( ... [-np.pi / 2, -4], [np.pi / 2, 4], (10, 8)) >>> det = CylindricalDetector( ... part, axes=[(1, 0, 0), (0, 0, 1)], radius = 2) >>> det.surface([0, 0]) array([ 0., 0., 0.]) >>> np.round(det.surface([np.pi / 2, 1]), 10) array([ 2., -2., 1.])
It is also vectorized, i.e., it can be called with multiple parameters at once (or an n-dimensional array of parameters):
>>> # 3 pairs of parameters, resulting in 3 vectors >>> np.round(det.surface([[-np.pi / 2, 0, np.pi / 2], [-1, 0, 1]]), 10) array([[-2., -2., -1.], [ 0., 0., 0.], [ 2., -2., 1.]]) >>> # Pairs of parameters in a (4, 5) array each >>> param = (np.zeros((4, 5)), np.zeros((4, 5))) >>> det.surface(param).shape (4, 5, 3)